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Example 1: Advanced Calculus Problem – Integration of Multivariable Functions
Problem:
Evaluate the integral of the function \( f(x, y) = x^2y + 3xy^2 \) over the region \( R \), where \( R \) is the rectangle bounded by \( 0 \leq x \leq 3 \) and \( 0 \leq y \leq 2 \).
**Solution*
To evaluate this double integral, we first write the problem as:
\[
\int_0^3 \int_0^2 (x^2y + 3xy^2) \, dy \, dx
\]
We start by performing the integration with respect to \( y \) first.
\[
\int_0^2 (x^2y + 3xy^2) \, dy = \left[ x^2 \frac{y^2}{2} + 3x \frac{y^3}{3}
ight]_0^2
\]
Evaluating this expression at the limits \( y = 2 \) and \( y = 0 \), we get:
\[
= x^2 \left( \frac{2^2}{2}
ight) + 3x \left( \frac{2^3}{3}
ight)
\]
\[
= x^2(2) + 3 \frac{8}{3} )
\]
\[
= 2x^2 + 8x
\]
Now, we integrate the result with respect to \( x \):
\[
\int_0^3 (2x^2 + 8x) \, dx = \left[ \frac{2x^3}{3} + 4x^2
ight]_0^3
\]
Evaluating at \( x = 3 \) and \( x = 0 \):
\[
= \frac{2(3)^3}{3} + 4(3)^2
\]
\[
= \frac{2(27)}{3} + 4(9)
\]
\[
= 18 + 36 = 54
\]
Thus, the value of the integral is \( 54 \).
Example 2: Linear Algebra Problem – Eigenvalues of a Matrix
Problem:
Find the eigenvalues of the matrix:
\[
A = \begin{pmatrix} 4 & 1 \\ 2 & 3 \end{pmatrix}
\]
Solution:
To find the eigenvalues of a matrix, we must solve the characteristic equation:
\[
\text{det}(A - \lambda I) = 0
\]
Where \( A \) is the matrix, \( I \) is the identity matrix, and \( \lambda \) represents the eigenvalues. For the given matrix \( A \), we have:
\[
A - \lambda I = \begin{pmatrix} 4 - \lambda & 1 \\ 2 & 3 - \lambda \end{pmatrix}
\]
Now, we calculate the determinant:
\[
\text{det}(A - \lambda I) = (4 - \lambda)(3 - \lambda) - (1)(2)
\]
\[
= (4 - \lambda)(3 - \lambda) - 2
\]
\[
= 12 - 4\lambda - 3\lambda + \lambda^2 - 2
\]
\[
= \lambda^2 - 7\lambda + 10
\]
We now solve the quadratic equation:
\[
\lambda^2 - 7\lambda + 10 = 0
\]
Using the quadratic formula:
\[
\lambda = \frac{-(-7) \pm \sqrt{(-7)^2 - 4(1)(1}}{2(1)}
\]
\[
\lambda = \frac{7 \pm \sqrt{49 - 40}}{2}
\]
\[
\lambda = \frac{7 \pm \sqrt{9}}{2}
\]
\[
\lambda = \frac{7 \pm 3}{2}
\]
Thus, the two eigenvalues are:
\[
\lambda_1 = \frac{7 + 3}{2} = 5
\]
\[
\lambda_2 = \frac{7 - 3}{2} = 2
\]
Therefore, the eigenvalues of the matrix are \( \lambda_1 = 5 \) and \( \lambda_2 = 2 \).
Conclusion
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